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6u^2-13u+1=0
a = 6; b = -13; c = +1;
Δ = b2-4ac
Δ = -132-4·6·1
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{145}}{2*6}=\frac{13-\sqrt{145}}{12} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{145}}{2*6}=\frac{13+\sqrt{145}}{12} $
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